0=3x^2+96

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Solution for 0=3x^2+96 equation: 



0=3x^2+96

We move all terms to the left:

0-(3x^2+96)=0

We add all the numbers together, and all the variables

-(3x^2+96)=0

We get rid of parentheses

-3x^2-96=0

a = -3; b = 0; c = -96;
Δ = b2-4ac
Δ = 02-4·(-3)·(-96)
Δ = -1152
Delta is less than zero, so there is no solution for the equation

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